A dodecahedron is having 20 vertices and 30 edges. How many faces are there?

Here:
  Number of vertices (V) = 20
     Number of edges (E) = 30
Let the number of faces are F. Then using Euler's formula, we have
                  F + V = E + 2                                                      ...(1)
∴         Substituting the values of V and E in (1), we get
                   F + 20 = 30 + 2
rightwards double arrow              F + 20 = 32
rightwards double arrow                     F = 32 - 20
rightwards double arrow                     F = 12
   Thus, the required number of faces = 12.

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Name the following polyhedron.

How many faces, vertiecs and edges of this solid are there?

∵ The ends (bases) of the given solid are congruent rectilinear figure each of six sides.
∴ It is a hexagonal prism.
In a hexagonal prism, we have:
The number of faces = 8
The number of edges = 18
The number of vertices = 12

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Why the following solids are not polyhedron?
(i) A sphere.
(ii) A cone.
(iii) A cylinder.

Since, a polyhedron is a solid shape bounded by polygons. However, (i) a sphere, (ii) a cone and (iii) a cylinder are not polyhedron because they are made of polygons, i.e. their faces are not polygons.
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What Euler’s formula? Verify the Euler’s formula for a pentagonal prism.


If a polyhedron is having number of faces as F, number of edges as E and the number of vertices as V, then the relationship F + V = E + 2 is known as Euler’s formula. Following figure is a solid pentagonal prism.

If a polyhedron is having number of faces as F, number of edges as E

It has:
 Number of faces (F) = 7
 Number of edges (E) = 15
 Number of vertices (V) = 10
Substituting the values of F, E and V in the relation,
                     F + V = E + 2
we have  
                     7 + 10 = 15 + 2
rightwards double arrow                     17  = 17
Which is true, the Euler’s formula is verified. 

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A polyhedron is having 8 vertices and 12 edges. How many faces of it are there?

Number of vertices (V) = 8
   Number of edges (E) = 12
Let the number of faces = V
Now, using the Euler's formula
                   F + V = E + 2
we have
                   F + 8 = 12 + 2
rightwards double arrow              F + 8 = 14
rightwards double arrow                  F =  14 - 8 
rightwards double arrow                 F = 6
  Thus, the required number of faces = 6.

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